Problems on Numbers are among the most scoring and logic-driven topics in arithmetic. But many students find them confusing because numbers behave differently under operations; they combine, expand, cancel, or transform depending on the pattern inside the expression.
If you understand these three ideas:
✔ Structure of algebraic expressions
✔ How numbers expand or factorize
✔ How to recognize identity patterns
Then you can solve ANY number-based question effortlessly.
This Problems on Numbers guide covers all formulas, concepts, shortcuts, cases, factorization identities, FAQs, and exam tips, making it the perfect one-stop resource for competitive exams.
Quick Overview: Problems on Numbers Formulas
| Concept / Situation | Considered (Meaning of Terms) | Used (Purpose) | Formula (With Meaning of Symbols Inside Row) |
|---|---|---|---|
| Difference of Squares | a, b = any two numbers | To simplify product of binomials | (a + b)(a − b) = a² − b² |
| Square of Sum | a, b = two numbers/variables | To expand expressions | (a + b)² = a² + b² + 2ab |
| Square of Difference | a, b = two numbers | To expand or simplify | (a − b)² = a² + b² − 2ab |
| Square of Three Numbers | a, b, c = three variables | To expand expressions with 3 terms | (a + b + c)² = a² + b² + c² + 2(ab + bc + ca) |
| Sum of Cubes | a, b = two numbers | To factorize cube sum | a³ + b³ = (a + b)(a² − ab + b²) |
| Difference of Cubes | a, b = two numbers | To factorize cube difference | a³ − b³ = (a − b)(a² + ab + b²) |
| General Cube Identity | a, b, c = three numbers | To factorize 3-term cube expressions | a³ + b³ + c³ − 3abc = (a + b + c)(a² + b² + c² − ab − bc − ca) |
| Special Case Identity | a, b, c = numbers whose sum is zero | To simplify cube expressions quickly | If a + b + c = 0 → a³ + b³ + c³ = 3abc |
Formulas for Problems on Numbers
Below is the full formula explanation section, written in the same style as your Train Passing Object formulas.
1. Difference of Squares Formula (Fast Simplification Pattern)
When multiplying expressions like (a + b)(a − b), the middle terms cancel out automatically.
This formula is the shortcut to simplify such products quickly.
Formula: Difference of Squares
(a+b)(a−b)=a2−b2
Where:
- a = first number
- b = second number
Why this formula works
When expanded:
- (a × a) = a²
- (a × −b) = −ab
- (b × a) = +ab
- (b × −b) = −b²
The middle terms (−ab and +ab) cancel out.
So only:
a2−b2
remains.
Common mistakes students make
- Expanding manually and making sign errors
- Forgetting that middle terms always cancel
- Using this formula even when expressions are NOT in (a + b)(a − b) format
Key Tip:
Whenever two brackets have the same terms but opposite signs, apply this identity instantly.
Example
Simplify:
101 × 99
= (100 + 1)(100 − 1)
= 100² − 1²
= 10000 − 1
= 9999
2. Square of Sum Formula (Three-Term Expansion)
Used when expressions appear as (a + b)².
This identity helps expand without long multiplication.
Formula
(a+b)2 = a2+b2+2ab
Why this formula works
Binomial multiplication gives:
- a²
- ab
- ab
- b²
Combine ab + ab → 2ab
Common mistakes
- Missing the 2ab term
- Incorrectly squaring ab
- Changing sign mistakes
Example
(40 + 3)²
= 40² + 3² + 2(40 × 3)
= 1600 + 9 + 240
= 1849
3. Square of Difference Formula (Negative Sign Variation)
Formula
(a−b)2=a2+b2−2ab
Why this formula works
Middle terms become:
- (−ab) + (−ab) = −2ab
Common errors
- Writing +2ab instead of −2ab
- Forgetting to square both terms
Example
(15 − 2)²
= 15² + 2² − 2(15 × 2)
= 225 + 4 − 60
= 169
4. Square of Three Numbers (Three-Term Expansion)
Formula
(a+b+c)2 = a2+b2+c2+2(ab+bc+ca)
Why this formula works
When expanded, the expression has:
- Three squares
- Three pairwise products
Common mistakes
- Missing any pair product
- Incorrectly combining terms
Example
(1 + 2 + 3)²
= (1² + 2² + 3²) + 2(2 + 6 + 3)
= (1 + 4 + 9) + 2(11)
= 14 + 22
= 36
5. Sum of Cubes Formula (Important Factorization Identity)
Formula
a3+b3 = (a+b)(a2−ab+b2)
Why this formula works
The binomial (a + b) pairs with a specific trinomial which removes mixed ab terms during expansion.
Common mistakes
- Using the wrong trinomial sign
- Forgetting that cube expressions factor into two brackets
Example
Find factors of:
8 + 27
= 2³ + 3³
= (2 + 3)(2² − 2×3 + 3²)
= 5(4 − 6 + 9)
= 5 × 7
= 35
6. Difference of Cubes Formula
Formula
a3−b3 = (a−b)(a2+ab+b2)
Why this formula works
The trinomial changes sign to maintain equality after expansion.
Common mistakes
- Writing minus inside trinomial
- Wrong pairing of signs
Example
125 − 64
= 5³ − 4³
= (5 − 4)(25 + 20 + 16)
= 1 × 61
= 61
7. General Cube Identity (Three-Variable Powerful Identity)
Formula
a3+b3+c3−3abc = (a+b+c)(a2+b2+c2−ab−bc−ca)
Why this formula works
It handles complex three-number cube expressions by splitting them into a binomial and a trinomial.
Common mistakes
- Mixing signs
- Forgetting the −3abc term
Example (Wider Calculation)
Let a = 1, b = 2, c = 3
Compute LHS:
1³ + 2³ + 3³ − 3(1)(2)(3)
= 1 + 8 + 27 − 18
= 18
Now RHS:
(1 + 2 + 3)(1² + 2² + 3² − 1·2 − 2·3 − 3·1)
= 6(1 + 4 + 9 − 2 − 6 − 3)
= 6(3)
= 18
Both match.
8. Special Case Identity
Condition
a+b+c = 0
Then
a3+b3+c3 = 3abc
Why this works
The entire first bracket (a + b + c) becomes zero in the general cube identity.
Example
Let a = 2, b = −1, c = −1
a + b + c = 0
So
a³ + b³ + c³ = 3abc
= 3(2)(−1)(−1)
= 6
Smart Tips and Practical Tricks for Solving Problems on Numbers
Mastering Problems on Numbers becomes simple when you understand how algebraic expressions behave during expansion and factorization. Most students make mistakes not because formulas are difficult, but because they apply them without identifying the correct pattern. This section breaks down the most important concepts into clear, actionable tips so you can solve questions faster and more accurately.
1. Identify the Pattern Before Using Any Formula
Most number identities follow recognizable patterns. If you detect the form square, cube, sum, or difference, solution becomes automatic.
Common patterns include:
- (a + b)² → Square of sum
- (a − b)² → Square of difference
- a³ ± b³ → Sum/Difference of cubes
- (a + b + c)² → Square of three numbers
- a³ + b³ + c³ − 3abc → General cube identity
Recognizing structure eliminates unnecessary steps and prevents guesswork.
2. Avoid Expanding Expressions Manually
Manually multiplying terms leads to mistakes and takes longer. Identities exist to simplify:
- (a + b)(a − b) = a² − b²
- (a + b)² = a² + b² + 2ab
Using identities reduces multi-step multiplication to one clean formula, improving speed and accuracy.
3. Check for the Special Shortcut: a + b + c = 0
This is one of the most powerful tricks in number system problems.
If
a+b+c = 0
Then
a3+b3+c3 = 3abc
This instantly simplifies large cube expressions and saves significant time in exams.
4. Convert Complicated Numbers Into Identity Form
Rewrite numbers to match patterns:
- 51 = 50 + 1 → (a + b)² pattern
- 99 = 100 − 1 → (a − b)² pattern
- 999 = 1000 − 1 → a³ − b³ pattern
This approach reduces heavy calculations into quick identity-based shortcuts.
5. Analyze the Structure Before Deciding the Identity
For example:
- If you see three variables together → try (a + b + c)² or cube identity
- If you see symmetry → square identity likely applies
- If cubes appear → factor using a³ ± b³ formula
Correctly selecting the identity is more important than memorizing formulas.
6. Double-Check the Signs (+ / −)
One of the most common mistakes:
Students mix up
✔ (a + b)² with (a − b)²
✔ a³ + b³ with a³ − b³
Your identity changes entirely based on the sign.
Always re-check:
✔ Is the middle sign plus or minus?
✔ Are the cubes added or subtracted?
✔ Is the final expression factorizable?
7. Practice Typical Competitive Exam Patterns
Most exam questions follow repetition-based patterns:
- Expand using (a + b)²
- Factorize using a³ − b³
- Use special case a + b + c = 0
- Apply (a + b)(a − b) to simplify
Practicing these patterns increases recognition speed, leading to faster solving during exams.
FAQs About Problems on Numbers
Q1. Why are algebraic identities important in number problems?
They simplify big expressions into smaller ones, helping you avoid long multiplications and reduce calculation mistakes.
Q2. When should I use (a + b)(a − b) = a² − b²?
Whenever two expressions differ only by sign, such as 101×99 → (100+1)(100−1).
Q3. Why are square formulas used so often in number questions?
Many expressions appear in squared form. Using identities expands them instantly without manual calculation.
Q4. How do I know whether to use sum or difference of cubes?
Check the connecting sign:
- “+” → use a³ + b³
- “−” → use a³ − b³
Q5. Why is the identity (a + b + c)² useful?
It simplifies expressions containing three terms, which frequently appear in reasoning and aptitude exams.
Q6. When can I apply the shortcut a³ + b³ + c³ = 3abc?
Only when a + b + c = 0. This condition is essential and must always be checked first.
Q7. Why do students often get identity-based questions wrong?
They fail to recognize the correct pattern and expand terms manually, which leads to errors in signs and multiplication.
Q8. How does recognizing patterns help in number problems?
Patterns indicate the identity to apply. Once the pattern is spotted, the question solves itself in 1–2 steps.
Q9. Why are cube identities used in higher-level exams?
Cube identities handle complex expressions quickly and eliminate large multiplications that would otherwise take long time.
Q10. What is the fastest way to master number identities?
Focus on pattern recognition, use identities instead of manual expansion, and practice frequently asked forms repeatedly.